Replace href value in anchor tags of html using XSLT -
i want replace value of href tags in html using xslt. example: if anchor tag <a href="/dir/file1.htm" />
, want replace href value this: <a href="http://site/dir/file1.htm" />
. point want replace relative urls absolute values.
i want anchor tags in html content. how can using xslt?
thanks.
edit: google appliance. display results in frame , links doesn't work in cached page. takes address bar url root. here html in form of string, , displays html based on condition. can suggest way replace href tags in string?
this xslt 1.0 transformation:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform"> <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/> <xsl:param name="pservername" select="'http://myserver'"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="a/@href[not(starts-with(.,'http://'))]"> <xsl:attribute name="href"> <xsl:value-of select="concat($pservername, .)"/> </xsl:attribute> </xsl:template> </xsl:stylesheet>
when applied xml document:
<html> <a href="/dir/file1.htm">link 1</a> <a href="/dir/file2.htm">link 2</a> <a href="/dir/file3.htm">link 3</a> </html>
produces wanted, correct result:
<html> <a href="http://myserver/dir/file1.htm">link 1</a> <a href="http://myserver/dir/file2.htm">link 2</a> <a href="http://myserver/dir/file3.htm">link 3</a> </html>
ii. xslt 2.0 solution:
in xpath 2.0 1 can use standard function resolve-uri()
this transformation:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform" xmlns:xs="http://www.w3.org/2001/xmlschema"> <xsl:variable name="vbaseuri" select="'http://myserver/ttt/x.xsl'"/> <xsl:template match="/"> <xsl:value-of select="resolve-uri('/mysite.aspx', $vbaseuri)"/> </xsl:template> </xsl:stylesheet>
when applied on xml document (not used), produces wanted, correct result:
http://myserver/mysite.aspx
if stylesheet module comes same server relative urls resolved, there no need pass base uri in parameter -- doing following produces wanted result:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform" xmlns:xs="http://www.w3.org/2001/xmlschema"> <xsl:variable name="vbaseuri"> <xsl:for-each select="document('')"> <xsl:sequence select="resolve-uri('')"/> </xsl:for-each> </xsl:variable> <xsl:template match="/"> <xsl:value-of select="resolve-uri('/mysite.aspx', $vbaseuri)"/> </xsl:template> </xsl:stylesheet>
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