python - Finding elements not in a list -
so heres code:
item = [0,1,2,3,4,5,6,7,8,9] item in z: if item not in z: print item
z contains list of integers. want compare item z , print out numbers not in z when compared item. can print elemtens in z when compared not items, when try , opposite using code above nothing prints.
any help?
your code not doing think think doing. line for item in z:
iterate through z
, each time making item
equal 1 single element of z
. original item
list therefore overwritten before you've done it.
i think want this:
item = [0,1,2,3,4,5,6,7,8,9] element in item: if element not in z: print element
but like:
set(item) - set(z)
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