Bash echo all array members when array is referenced as a variable in a loop -

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the "echo" below failing , retarded figure out why. trying echo of array members in loop.

#!/bin/bash foo=bar1,bar2 in ${foo//,/" "} declare -a ${i}='(null null null null)' echo ${i[*]} done

thanks help!

try eval "echo \${$i[*]}"

why doing way? there easier , more direct way whatever ultimate goal is. if describe it, perhaps can avoid unnecessary complication.


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