C++ syntax for explicit specialization of a template function in a template class? -

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i have code works in vc9 (microsoft visual c++ 2008 sp1) not in gcc 4.2 (on mac):

struct tag {};  template< typename t > struct c {        template< typename tag >     void f( t );                 // declaration      template<>     inline void f< tag >( t ) {} // error: explicit specialization in };                               // non-namespace scope 'structc<t>'

i understand gcc me move explicit specialization outside class can't figure out syntax. ideas?

// following not correct syntax, is? template< typename t > template<> inline void c< t >::f< tag >( t ) {}

you can't specialize member function without explicitly specializing containing class.
can forward calls member function of partially specialized type:

template<class t, class tag> struct helper {     static void f(t);    };  template<class t> struct helper<t, tag1> {     static void f(t) {} };  template<class t> struct c {     // ...     template<class tag>     void foo(t t) {         helper<t, tag>::f(t);     } };

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