python - Finding elements not in a list -

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so heres code:

item = [0,1,2,3,4,5,6,7,8,9]  item in z:     if item not in z:         print item

z contains list of integers. want compare item z , print out numbers not in z when compared item. can print elemtens in z when compared not items, when try , opposite using code above nothing prints.

any help?

your code not doing think think doing. line for item in z: iterate through z, each time making item equal 1 single element of z. original item list therefore overwritten before you've done it.

i think want this:

item = [0,1,2,3,4,5,6,7,8,9]  element in item:     if element not in z:         print element

but like:

set(item) - set(z)

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