c - Getting the address of a triple pointer to char -

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gcc 4.4.4 c89

i wondering why getting different memory address. when print address of animals in main following:

animals [ rabbit ] : [ 0xbfab2e48 ] animals [ rabbit ] : [ 0xbfab2e48 ]

however, when print in function, different memory locations. think should same.

ptr animals [ rabbit ] : [ 0xbfab2e08 ] ptr animals [ rabbit ] : [ 0xbfab2e08 ]

many advice,

int main(void) {     char *animals[] = {"rabbit", "cat", "dog", "elephant", "racoon", null};     char *countries[] = {"india", "amercia", "france", "spain", "canada", "mexico", null};     char *cars[] = {"ford fista", "masda 3", "honda city", "toyata cote", null};     char **ptr_data[] = {animals, countries, cars, null};      printf("animals [ %s ] : [ %p ]\n", *animals, (void*)animals);     printf("animals [ %s ] : [ %p ]\n", animals[0], &animals[0]);      print_data_ptr(ptr_data);      return 0; }  void print_data_ptr(char ***ptr) {     char **data_list = null;      printf("ptr animals [ %s ] : [ %p ]\n", *ptr[0], (void*)&ptr[0]);     printf("ptr animals [ %s ] : [ %p ]\n", **ptr, (void*)ptr); }

animals array of char * values, , ptr_data array of char ** values.

when initialise ptr_data in line:

char **ptr_data[] = {animals, countries, cars, null};

animals evaluated pointer first element - ptr_data[0] same &animals[0] - address of first char * in animals. same thing happens in 2 printf() functions in main - animals , &animals[0] evaluate same thing, pointer value stored in ptr_data[0].

within function, ptr pointer first element of ptr_data in main - ptr equivalent &ptr_data[0]. &ptr[0] equivalent ptr - &ptr[0] shows address of ptr_data[0], not stored there. if print ptr[0] instead, address of animals[0].


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